求vb点虐 的源代码，最好说明其解决问题，越多越好，满意加50分。

下埋凳面这段代码，是我用来计算每个月存500元进银行，连续30年，最颂液余后连本带利能有多少钱。这里面涉及复利计算。界面中右边的文本框用来输出每一次计算的结果。

在古浪等地区，都构建了全面的区域性战略布局，加强发展的系统性、市场前瞻性、产品创新能力，以专注、极致的服务理念，为客户提供成都做网站、成都网站设计 网站设计制作按需搭建网站,公司网站建设,企业网站建设,品牌网站建设,全网营销推广,成都外贸网站建设,古浪网站建设费用合理。

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

  Dim nianxian As Integer '年限变量

  Dim dingcun As Integer '定存变量

  Dim fuli_big As Long '大复利

  Dim fuli_small As Long '小复利

  Dim i As Integer '循环变量

  Dim DATAstring As String '数据字符串

  nianxian = Val(年限_TextBox.Text)

  dingcun = Val(定存_TextBox.Text)

野滚     DATAstring = ""

  For i = 1 To nianxian

      fuli_small = dingcun * (1 + 0.1875)

      dingcun = fuli_small

      fuli_big = fuli_big + fuli_small

      DATAstring = DATAstring + "[" + Trim(Str(i)) + "]" + Str(fuli_big) + Chr(13) + Chr(10)

      'DATAstring = DATAstring + "[" + Trim(Str(i)) + "]" + Str(fuli_small) + Chr(13) + Chr(10)

  Next

  'fuli_big = fuli_small

  TextBox1.Text = DATAstring

  结果_TextBox.Text = Str(fuli_big) + "元"

End Sub

VB 解一元二次方程程序设计

vb代码饥祥雀如下：

Private Sub Command1_Click()

Dim a As Single, b As Single, c As Single

Dim d As Single, x1 As Single, x2 As Single

a = InputBox("请输入一元二次方程的系数a")

b = InputBox("请输入一元二次方程的系数b")

c = InputBox("请输入一元二次方程的系数c")

If a = 0 Then

a = InputBox("因为a≠0，你输入的a＝烂早0，请重新输入系数a")

End If

d = b * b - 4 * a * c

If d = 0 Then

x1 = (-b + Sqr(d)) / (2 * a)

x2 = (-b - Sqr(d)) / (2 * a)

Print "系数为"; a; b; c; "的一元二次方程的根分别为"; x1

Print "系数为"; a; b; c; "的一元二次方程的根分别为"; x2

Else

Print "此方程在实数范围内无解"

End If

End Sub

一、按钮“求一元二次方程”的vb代码如下：

Private Sub Command1_Click()

a = Text1.Text

b = Text2.Text

c = Text3.Text

d = b * b - 4 * a * c

If d = 0 Then

X1 = (-b + Sqr(d)) / (2 * a)

X2 = (-b - Sqr(d)) / (2 * a)

Label4.Caption = X1

Label5.Caption = X2

Else

Label4.Caption = "在实数范围内无解"

End If

End Sub

二、按钮“重置”的vb代码如下：

Private Sub Command2_Click()

Text1.Text = ""

Text2.Text = ""

Text3.Text = ""

Label4.Caption = ""

Label5.Caption = ""

End Sub

三、按钮“退出”的vb代码如下：

Private Sub Command3_Click()

End

End Sub

特殊例子（指定系数c的值为5）：

在窗体“Form1.frm”的“Command1_click“事件中编写代码（请不要随便更改其它代码），使之能够实现如下功能：在Text1输入整数a、、Text2输入b，判断一元二次方程ax2+bx+5=0有无实数根。并在Text3文本框中显示判断结果，即有实数根则在Text3文本框中输出“有”，否则输出“无”。

VB程序代码如下：

Private Sub Command1_Click()

dim a as single,b as single

a = Text1.Text

b = Text2.Text

d = b * b - 4 * a * 5

If d = 0 Then

Text3.Text="有"

Else

Text3.Text="无"

End If

End Sub

如果不用dim定义变量，则上面的输入部分语句改为下面的语句，这样可以宴世把字符变量类型转化为数值类型：

a =val(Text1.Text)

b =val(Text2.Text)

楼主.给你写这么呢多你不给加点分吗?= =||

VB解方程

解一元一次方程：

设置4个文本框，分别代表一元一次方程中的参数k,b,x,y

分别命名txtk,txtb,txtx,txty.计算按钮命名为cmdCalc。

在代码窗口里粘贴如下代码:

Private Sub cmdCalc_Click()

Dim k, b As Long

k = txtk.Text

b = txtb.Text

If txtx.Text = "x" Then

MsgBox "x的值为:" (txty.Text - b) / k

ElseIf txty.Text = "y" Then

MsgBox "y的值为宴早睁:" k * txtx.Text + b

End If

End Sub

计算时求x则在txtx那里输入一个x，

求y则在txty那里输入一个y，

在各文本框中输入参数，

然后按下按钮，

就有提示框弹出，显示结果。

一元二次方程：

privat sub command1_click()

dim a,b,c,x1,x2,d as sigle

a=val(textl.text)

b=val(text2.text)

c=val(text3.text)

d=b^2-4*a*c

if d0 then

x1=(-b+sqr(d))/(2*a)

x2=(-b-sqr(d))/(2*a)

else if d=0 then

x1=(-b/2*a)

x2=x1

else msgbox"方程没有实根"

end if

text4.text="x1=" x1 "" "x2=" x2

end sub

sub min(byref a() as integer)

dim i,j as interger

for i=1 to 9

for j=i+1 to 10

if a a(i)a(j) then

t=a(j)

a(i)=a(j)

a(j)=t

end if

next

next

end sub

private sub command_(click)

dim b(1 to 10) as interger

dim a(1 to 10) as interger

randomize

for i=1 to 10

a(i)=int(rnd*90)+10

list1.additem a(i)

b(i)=int(rnd*90)+ 10

list2.additem b(i)

next

call min(a)

call min(b)

if a(1)b(1) then

m=a(1)

else

m=b(1)

end if

text1.text="A,B种的最小值：" vbcrlf m

end sub

一元三次晌岁方程：

针对方程"ax^3+bx^2+cx+d=0"的求根程序。

控件只需一个Command1，结果显示在“立即”中。

代码如下。（参睁皮考）

========================

Private Sub Command1_Click()

Dim x1r As Double, x1i As Double, x2r As Double, x2i As Double, x3r As Double, x3i As Double

Dim ret As String

Const eq = "ax^3+bx^2+cx+d=0"

a = InputBox("请输入a", eq)

b = InputBox("请输入b", eq)

c = InputBox("请输入c", eq)

d = InputBox("请输入d", eq)

ret = CubicEquation(a, b, c, d, x1r, x1i, x2r, x2i, x3r, x3i) '5x^3+4x^2+3x-12=0

Debug.Print "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" ret

Debug.Print x1r; " + "; x1i; " i"

Debug.Print x2r; " + "; x2i; " i"

Debug.Print x3r; " + "; x3i; " i"

End Sub

Private Function CubicEquation _

(ByVal a As Double, ByVal b As Double, ByVal c As Double, ByVal d As Double, _

x1r As Double, x1i As Double, x2r As Double, x2i As Double, x3r As Double, x3i As Double) As String

'Cubic equation(v2.2), coded by btef (please let this line remain)

Dim e As Double, f As Double, g As Double, h As Double, delta As Double

Dim r As Double, sita As Double, pi As Double, rr As Double, ri As Double

If a = 0 Then

CubicEquation = "Not a cubic equation: a = 0"

Exit Function

End If

'pi = 3.14159265358979

pi = 4 * Atn(1)

b = b / a 'simplify to a=1: x^3+bx^2+cx+d=0

c = c / a

d = d / a

e = -b ^ 2 / 3 + c 'substitute x=y-b/3: y^3+ey+f=0

f = (2 * b ^ 2 - 9 * c) * b / 27 + d

If e = 0 And f = 0 Then

x1r = -b / 3

x2r = x1r

x3r = x1r

CubicEquation = "3 same real roots:"

ElseIf e = 0 Then 'need to deal with e = 0, or it will cause z = 0 later.

r = -f 'y^3+f=0, y^3=-f

r = Cur(r)

x1r = r - b / 3 'a real root

If r 0 Then 'r never = 0 since g=f/2, f never = 0 there

sita = 2 * pi / 3

x2r = r * Cos(sita) - b / 3

x2i = r * Sin(sita)

Else

sita = pi / 3

x2r = -r * Cos(sita) - b / 3

x2i = -r * Sin(sita)

End If

x3r = x2r

x3i = -x2i

CubicEquation = "1 real root and 2 image roots:"

Else 'substitute y=z-e/3/z: (z^3)^2+fz^3-(e/3)^3=0, z^3=-g+sqr(delta)

g = f / 2 '-q-sqr(delta) is ignored

h = e / 3

delta = g ^ 2 + h ^ 3

If delta 0 Then

r = Sqr(g ^ 2 - delta)

sita = Argument(-g, Sqr(-delta)) 'z^3=r(con(sita)+isin(sita))

r = Cur(r)

rr = r - h / r

sita = sita / 3 'z1=r(cos(sita)+isin(sita))

x1r = rr * Cos(sita) - b / 3 'y1=(r-h/r)cos(sita)+i(r+h/r)sin(sita), x1=y1-b/3

sita = sita + 2 * pi / 3 'no image part since r+h/r = 0

x2r = rr * Cos(sita) - b / 3

sita = sita + 2 * pi / 3

x3r = rr * Cos(sita) - b / 3

CubicEquation = "3 real roots:"

Else 'delta = 0

r = -g + Sqr(delta)

r = Cur(r)

rr = r - h / r

ri = r + h / r

If ri = 0 Then

CubicEquation = "3 real roots:"

Else

CubicEquation = "1 real root and 2 image roots:"

End If

x1r = rr - b / 3 'a real root

If r 0 Then 'r never = 0 since g=f/2, f never = 0 there

sita = 2 * pi / 3

x2r = rr * Cos(sita) - b / 3

x2i = ri * Sin(sita)

Else 'r 0

sita = pi / 3

x2r = -rr * Cos(sita) - b / 3

x2i = -ri * Sin(sita)

End If

x3r = x2r

x3i = -x2i

End If

End If

End Function

Private Function Cur(v As Double) As Double

If v 0 Then

Cur = -(-v) ^ (1 / 3)

Else

Cur = v ^ (1 / 3)

End If

End Function

Private Function Argument(a As Double, b As Double) As Double

Dim sita As Double, pi As Double

'pi = 3.14159265358979

pi = 4 * Atn(1)

If a = 0 Then

If b = 0 Then

Argument = pi / 2

Else

Argument = -pi / 2

End If

Else

sita = Atn(Abs(b / a))

If a 0 Then

If b = 0 Then

Argument = sita

Else

Argument = -sita

End If

ElseIf a 0 Then

If b = 0 Then

Argument = pi - sita

Else

Argument = pi + sita

End If

End If

End If

End Function

二元一次方程：

Dim a, b, c As Integer

Dim x, y As Single

Dim d As Double

a = Val(InputBox("输入二次项系数"))

b = Val(InputBox("输入一次项系数"))

c = Val(InputBox("输入常数项"))

d = b ^ 2 - 4 * a * c

If d 0 Then

MsgBox "方程无解"

ElseIf d = 0 Then

x = -b / (2 * a)

MsgBox "方程有一个解：" x

Else

x = (-b + Sqr(d)) / (2 * a)

y = (-b - Sqr(d)) / (2 * a)

MsgBox "方程有两个解：" x "和" y

End If

三元一次方程：

方程组如下,

ax+by+cz=d

a'x+b'y+c'z=d'

a"x+b"y+c"z=d"

其中x,y,z为未知数,a,a',a",b,b',b",c,c',c",d,d',d",为用户输入的数值

解N元一次方程，indat为N+1行、N列的数组，outdat为N个元素的数组

Public Sub 解方程(ByRef InDat() As Double, ByVal InDatCount As Long, ByRef OutDat() As Double, ByRef OutDatCount As Long)

Dim Xt() As Double

Dim Dt As Double

Dim Ss As Long

Dim OtSCount As Long

Dim XtOut() As Double

If InDatCount 1 Then

ReDim Xt(1 To InDatCount - 1, 1 To InDatCount) As Double

For j = 1 To InDatCount - 1 '行

For i = 2 To InDatCount + 1 '列

Xt(j, i - 1) = InDat(j, i) * InDat(InDatCount, 1) / InDat(1, 1) - InDat(InDatCount, i)

Next i

Next j

OtSCount = 0

解方程 Xt, InDatCount - 1, XtOut, OtSCount

Dt = 0

For i = 1 To InDatCount - 1

Dt = Dt + InDat(InDatCount, i + 1) * XtOut(i)

Next i

Dt = Dt + InDat(InDatCount, i + 1)

ReDim Preserve OutDat(1 To 1 + OtSCount) As Double

OutDat(1) = -Dt / InDat(InDatCount, 1)

For i = 2 To OtSCount + 1

OutDat(i) = XtOut(i - 1)

Next i

OutDatCount = 1 + OtSCount

Else

ReDim OutDat(1 To 1) As Double

If InDat(1, 1) 0 Then

OutDat(1) = -InDat(1, 2) / InDat(1, 1)

Else

OutDat(1) = 0

End If

OutDatCount = 1

End If

End Sub

网页题目：vb点虐 解方程源码 vb开方代码
网站路径：http://pwwzsj.com/article/ddpogeo.html