怎么使用堆数据结构来计算和更新模块度 java代码

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{

if(cmd[i]

}

else if(cmd == "

struct

File

{

string name;

string htmp = hint; pCur-pPre =

pF-

File(){name = "!"

while(cur ;

}

}

else if(cmd ==

".pos;

pCur = pRoot-.isDir;输入分区数;

vector)

{

cin

iomanip

pos += f; cmd[i]

pNxt;++i)

{

find = false这是我们做的; hint.Run().size(); endl;

cur =

cur- endl;"string string

File* tar =

pCur-

f;\

return tail-;pChd-\

}

Rd(tar);

if(end

== -1)

break;pNxt-

Show(pCur-pChd = tail-

beg = 0.pChd =

f.find('

tail-",f);

return 0;a'pNxt-

f;

int

main()

{

DirSystem ds;

hint += "

bool find =

false;

}

else

{

if(nm;i ++i)

{

cout

tail-.size();

File* pPre!= NULL)

cout ,f);

num，拒绝删除;pChd.size()

while(tmp-

while(true)

{

res;pNxt;

ds;

cin

a'

Md(pCur;pNxt = new File;

File* ftmp = pCur;pNxt =

pF-

else if(pF-

string hint;

}

string Uniform(string

cmd)

{

string res = cmd;\name

f;pChd = new

File;

else

break;)

{

cin

for(int i = 0.pChd =

f;

tail-pPar = pRoot;

else

{

pF-RD" nm =

Parse(cmd);pNxt;

ds;

cmd = Uniform(cmd):"!find)

{

pCur =

ftmp;pNxt-

end = tar;

int offset = 'pChd ; -

',beg),f);

f;\

}

else

{

cout

int i;isDir)

cout

.pPar = f,end - beg)).pNxt = f;

}

return res.len!=

NULL)

pF-

if(cmd == "pNxt-

public;

bool isDir;isDir

= false; name,*t;

beg = end + 1; "!= NULL)

tmp =

tmp-.push_back(tar;}

};

hint = " cmd;

end = tar;)

{

cin

A'string.erase(hint; endl; "

hint = htmp;,beg); cmd;pNxt-

Parse(string tar)

{

vector

}

else

{

File* tmp = pCur-=

'

else

cout

File* pNxt;pNxt;pPre = tail;);

}

else if(cmd

== ".isDir = true;

if(pF-)

res[i] = cmd[i] +

offset;pChd.Init(),pos;

cout .find('pNxt-= 'i ,tmp; "name ==

nm[i])

{

hint += nm[i] + ' endl; ",f);\.pos = 0;

}

}

void

Rd(File* pF)

{

if(pF == NULL)

cout

pNxt;

f;pChd;;您输入的命令本系统不识别;

find = true; nm.pPar = f!=

cmd)

tar = tar-

f.name = ch++ + string("

tail-

}

return res;(文件) "

for(int i = 0;"MF"

f!"\vectorpos = f;

endl;

while(true)

{

cout res; "z'

cout

pChd);

}

if(;

#include ,f); "该文件夹中还有其它文件;pChd- endl;

cur-

cin

File f;

int

beg;

}

}

}

private;

}

}

void Init()

{

int

num;pPre-.pNxt = f;string.len = 100;

File f;pNxt ;

while(pCur

;没有找到要转向的路径;

}

}

void Run()

{

File* pCur;

tail-

cmd;iostreampNxt;输入分区容量;

break:

vectorpPar = pCur;)

{

cin

,const File f)

{

if(pCur-

cmd;

}

};

while(tar)

{

if(tar-

MD"

Md(pCur.len.substr(beg;pNxt-len = f;

File*

pPar;

}

else if(cmd == "

}

if(;

f;pNxt.pos = 0;pChd;

pos =

0;C'

tail-

hint = pCur-

f,end;pos = len = 0;

}

pCur =

pCur-

for(i = 0; endl; ".pPre = NULL;;

int

len;

if(cur-.isDir = false; cmd; f;;!find)

break;

char ch =

')

{

cout :"pPar = NULL;';

f;DIR".pPar = f;pNxt ;}

File*

Append(File* tail;'

delete pF;pPre;;

t =

Append(t.len.end()-1).len = 100;.pChd = f;

cmd = Uniform(cmd);i

pNxt-(文件夹) "

#include '

f;

Append(pCur-;;

endl,cmd;

f;

pCur-pNxt; "!" endl;pChd = new File.name =

cmd;:4786)

#include

pCur = pRoot;pChd = pPar = pPre =

pNxt = NULL;\:

DirSystem(){pRoot = new File;

cin

using namespace

std;

class DirSystem

{

private.name = cmd;name ;\pNxt; cmd,const

File f)

{

tail-name = f;

f;

File f;

int

pos;.pPre = NULL;

Append(tmp.isDir = true;

f.pNxt = f;pChd ==

NULL)

{

pCur-pNxt-:"pRoot-pNxt = tail-

File* pChd!=

NULL)

{

if(pCur- num;!= NULL)

{

cout

1)

hint;CD"

File* cur = pF-

}

}

void Show(File*

pF)

{

if(pF == NULL)

return;isDir = f;

}

void Md(File*

pCur!"文件不存在;":

File* pRoot;

pCur = pCur-pChd-name + ".pPre =

NULL.pos = pos;pRoot-.name;

t = pRoot-、基本上满足你的要求

#pragma

warning(disable;

#include

关于数据结构（java）的一个代码

描述栈抽象数据类型的SStack接口的声明

public interfaceSStackE //栈接口

{

boolean isEmpty(); //判断是否空栈，若空栈返回true

boolean push(E element); //元素element入栈，若操作成功返回true

E pop(); //出栈，返回当前栈顶元素，若栈空返回null

E get(); //取栈顶元素值，未出栈，若栈空返回null

}

顺序栈类具体操作方法的声明：

importdataStructure.linearList.SStack;

public classSeqStackE implements SStackE

//顺序栈类

{

private Object value[]; //存储栈的数据元素

private int top; //top为栈顶元素下标

public SeqStack(int capacity) //构造指定容量的空栈

{

this.value = newObject[Math.abs(capacity)];

this.top=-1;

}

public SeqStack() //构造默认容量的空栈

{

this(10);

}

public boolean isEmpty() //判断是否空栈，若空栈返回true

{

return this.top==-1;

}

public boolean push(E element) //元素element入栈，若操作成功返回true

{

if (element==null)

return false; //空对象（null）不能入栈

if (this.top==value.length-1) //若栈满，则扩充容量

{

Object[] temp = this.value;

this.value = newObject[temp.length*2];

for (int i=0; itemp.length;i++)

this.value[i] = temp[i];

}

this.top++;

this.value[this.top] = element;

return true;

}

public E pop() //出栈，返回当前栈顶元素，若栈空返回null

{

if (!isEmpty())

return (E)this.value[this.top--];

else

return null;

}

public E get() //取栈顶元素值，未出栈，栈顶元素未改变

{

if (!isEmpty())

return (E)this.value[this.top];

else

return null;

}

public String toString() //返回栈中各元素的字符串描述

{

String str="{";

if (this.top!=-1)

str +=this.value[this.top].toString();

for (int i=this.top-1; i=0; i--)

str += ","+this.value[i].toString();

return str+"} ";

}

实例引用public static void main(String args[])

{

SeqStackString stack = newSeqStackString(20);

System.out.print("Push: ");

char ch='a';

for(int i=0;i5;i++)

{

String str =(char)(ch+i)+"";

stack.push(str);

System.out.print(str+" ");

}

System.out.println("\n"+stack.toString());

System.out.print("Pop : ");

while(!stack.isEmpty()) //全部出栈

System.out.print(stack.pop().toString()+" ");

System.out.println();

}

java编程，设T是存储n个整数的堆。编写程序，完成堆这种数据结构的基本操作，并增加一个操作为：i

public class Test {

private static int a = 1678;

public static void main(String[] args) {

String b = String.valueOf(a);

for(int i=0;ib.length();i++){

System.out.println(b.charAt(i));

}

}

}

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