java解析lrc文件代码

lrc可以通过如下util工具类进行转换，如果想知道结果是否读取的有问题，可以直接用记事本打开lrc文件的，之后和输出结果比对一下就行。

麻章网站建设公司创新互联,麻章网站设计制作，有大型网站制作公司丰富经验。已为麻章超过千家提供企业网站建设服务。企业网站搭建\外贸营销网站建设要多少钱，请找那个售后服务好的麻章做网站的公司定做！

package com.routon.utils;

import java.io.BufferedReader;

import java.io.FileInputStream;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.ArrayList;

import java.util.List;

import java.util.regex.Matcher;

import java.util.regex.Pattern;

import android.util.Log;

/**

* parse lrc file tool

* eg：

* utilLrc lrc = new utilLrc("/sdcard/test.lrc");

* get song name : String title = lrc.getTitle();

* get performer name : String artist = lrc.getArtist();

* get album name: String album = lrc.getAlbum();

* get lrcmaker name: String lrcMaker = lrc.getLrcMaker();

* get song list: ListStatement list = lrc.getLrcList();

*

* @author xuweilin

*

*/

public class utilLrc {

private static String TAG = "utilLrc";

public class Statement {

private double time = 0.0; //time, 0.01s

private String lyric = ""; //song word

/*

* get time

*/

public double getTime() {

return time;

}

/*

* set time

*/

public void setTime(double time) {

this.time = time;

}

/*

* set time.format:mm:ss.ms

*/

public void setTime(String time) {

String str[] = time.split(":|\\.");

this.time = Integer.parseInt(str[0])*60+Integer.parseInt(str[1])+Integer.parseInt(str[2])*0.01;

}

/*

* get lrc word

*/

public String getLyric() {

return lyric;

}

/*

* set lrc word

*/

public void setLyric(String lyric) {

this.lyric = lyric;

}

}

private BufferedReader bufferReader = null;

private String title = "";

private String artist = "";

private String album = "";

private String lrcMaker = "";

private ListStatement statements = new ArrayListStatement();

/*

*

* fileName

*/

public utilLrc(String fileName) throws IOException{

FileInputStream file = new FileInputStream(fileName);

bufferReader = new BufferedReader(new InputStreamReader(file, "utf-8"));

readData();

}

/*

* read the file

*/

private void readData() throws IOException{

statements.clear();

String strLine;

while(null != (strLine = bufferReader.readLine()))

{

if("".equals(strLine.trim()))

{

continue;

}

if(null == title || "".equals(title.trim()))

{

Pattern pattern = Pattern.compile("\\[ti:(.+?)\\]");

Matcher matcher = pattern.matcher(strLine);

if(matcher.find())

{

title=matcher.group(1);

continue;

}

}

if(null == artist || "".equals(artist.trim()))

{

Pattern pattern = Pattern.compile("\\[ar:(.+?)\\]");

Matcher matcher = pattern.matcher(strLine);

if(matcher.find())

{

artist=matcher.group(1);

continue;

}

}

if(null == album || "".equals(album.trim()))

{

Pattern pattern = Pattern.compile("\\[al:(.+?)\\]");

Matcher matcher = pattern.matcher(strLine);

if(matcher.find())

{

album=matcher.group(1);

continue;

}

}

if(null == lrcMaker || "".equals(lrcMaker.trim()))

{

Pattern pattern = Pattern.compile("\\[by:(.+?)\\]");

Matcher matcher = pattern.matcher(strLine);

if(matcher.find())

{

lrcMaker=matcher.group(1);

continue;

}

}

int timeNum=0;

String str[] = strLine.split("\\]");

for(int i=0; istr.length; ++i)

{

String str2[] = str[i].split("\\[");

str[i] = str2[str2.length-1];

if(isTime(str[i])){

++timeNum;

}

}

for(int i=0; itimeNum;++i)

{

Statement sm = new Statement();

sm.setTime(str[i]);

if(timeNumstr.length)

{

sm.setLyric(str[str.length-1]);

}

statements.add(sm);

}

}

sortLyric();

}

/*

* judge the string is or not date format.

*/

private boolean isTime(String string)

{

String str[] = string.split(":|\\.");

if(3!=str.length)

{

return false;

}

try{

for(int i=0;istr.length;++i)

{

Integer.parseInt(str[i]);

}

}

catch(NumberFormatException e)

{

Log.e(TAG, "isTime exception："+e.getMessage());

return false;

}

return true;

}

/*

* sort the word by time.

*/

private void sortLyric()

{

for(int i=0;istatements.size()-1;++i)

{

int index=i;

double delta=Double.MAX_VALUE;

boolean moveFlag = false;

for(int j=i+1;jstatements.size();++j)

{

double sub;

if(0=(sub=statements.get(i).getTime()-statements.get(j).getTime()))

{

continue;

}

moveFlag=true;

if(subdelta)

{

delta=sub;

index=j+1;

}

}

if(moveFlag)

{

statements.add(index, statements.get(i));

statements.remove(i);

--i;

}

}

}

/**

* get title

* @return

*/

public String getTitle(){

return title;

}

/**

* get artist

* @return

*/

public String getArtist(){

return artist;

}

/**

* get album

* @return

*/

public String getAlbum(){

return album;

}

/**

* get lrc maker

* @return

*/

public String getLrcMaker(){

return lrcMaker;

}

/**

* get song list

* @return

*/

public ListStatement getLrcList(){

return statements;

}

}

求教，急用！JAVA按歌词文件的时间标签从小到大排列内容，然后最好能给我做个方法，让我直接调用，排

你好，这是你要的方法，直接输入路径调用就可以了，输出结果是sorted-加原文件名

/**

* 根据路径和编码 重新排列歌词中的文件，转换后的文件是“sorted-原文件”

*

* @param source 原文件

*/

public static void sortLyric(String source) {

try {

BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(source), "UTF-8"));

ListString lines = new ArrayListString();

String line;

while ((line = br.readLine()) != null) {

lines.add(line);

}

br.close();

Collections.sort(lines);

BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(new FileOutputStream("sorted-" + source, false), "UTF-8"));

for (String everyLine : lines) {

bw.write(everyLine);

bw.newLine();

bw.flush();

}

bw.close();

} catch (Exception e) {

e.printStackTrace();

}

}

在java中怎么从键盘输入一段歌词以空格用split()分割

public static void main(String[] args) {

// TODO 自动生成的方法存根

Scanner sc = new Scanner(System.in);

System.out.println("请输入歌词:");

String s = sc.nextLine();

String[] x = s.split(" ");

for(int i = 0;ix.length;i++){

System.out.println(x[i]);

}

}

JAVA截取字符串(截取歌词)

把歌词存在一个叫 geci.txt 的文本中 放在D盘根目录

import java.io.BufferedReader;

import java.io.FileNotFoundException;

import java.io.FileReader;

import java.io.IOException;

public class SaveSong {

/**

* @param args

*/

public static void main(String[] args) {

// TODO Auto-generated method stub

BufferedReader br = null;

String lineContent = "";

String[] s = new String[100];

int i = 0;

try {

br = new BufferedReader(new FileReader("D:\\geci.txt"));

} catch (FileNotFoundException e1) {

// TODO Auto-generated catch block

e1.printStackTrace();

}

try {

while ((lineContent = br.readLine()) != null) {

System.out.println(lineContent);

s[i]= lineContent;

i++;

}

} catch (IOException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

用java写程序 显示一首歌的一段歌词 并标注和声部分

很简单啊，创建一个类，再建一个方法，在里面创建一个String类型变量，里面放入你想放入的歌词，标注也可以加在里面。

java 正则表达式 匹配[00:00.00]或者[00:00]这两种歌词时间格式的正则表达式

下面的代码就是你想要的:

public static void main(String[] args) {

String regx1="\\[\\d{2}:\\d{2}.\\d{2}\\]";

String regx2="\\[\\d{2}:\\d{2}\\]";

Pattern p = Pattern.compile(regx1);

String str = "[124:00.00]";

Matcher m = p.matcher(str);

if(!m.matches()){

p = Pattern.compile(regx2);

m = p.matcher(str);

if(!m.matches()){

System.out.println("输入格式不符合要求!");

}else{

System.out.println("输入格式正确!　匹配格式为:"+"[00:00]");

}

}else{

System.out.println("输入格式正确!　匹配格式为:"+"[00:00.00]");

}

}

标题名称：java歌词代码,歌曲java
文章出自：http://pwwzsj.com/article/hspcij.html