leetCode12.IntegertoRoman|字符串|Medium

12. Integer to Roman

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Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

题目大意:

将一个给定的阿拉伯数字转换成罗马数字。

思路:

这题看到的时候,想的太多。

其实很简单,将千位,百位,十位,个位都表示出来,然后组合即可。

代码如下:

class Solution {
public:
    string intToRoman(int num) {
        string thousands[4] = {"","M","MM","MMM"};
        string hundreds[10] = {"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"};
        string tens[10] = {"","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"};
        string units[10] = {"","I","II","III","IV","V","VI","VII","VIII","IX"};

        string * hits[4] = {units,tens,hundreds,thousands};
        
        string result;
        int index = 0;
        while (num > 0)
        {
            result = hits[index][num % 10] + result;
            num = num / 10;
            index++;
        }
        
        return result;
    }
};

总结:

有时候题目没有那么难,不要自己搞的很复杂。问题简单化。简单化。。。

2016-08-19 15:16:29


分享标题:leetCode12.IntegertoRoman|字符串|Medium
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