C语言实现贪吃蛇游戏
最近整理下电脑，看到了自己在上个学期打的贪吃蛇游戏的c代码，觉得真的是略微有点冗长，但是实现起来应该也算是比较好理解，于是把自己的代码搬上来，网络上写贪吃蛇的c语言的文章很多，我这篇也仅是给大家作为一个参考而已。
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我的代码是在Windows下运行的，因为需要用到windows.h这个库。
然后也做了一个简单的ai模式，这在没有障碍物的情况下前期还是蛮不错的，但是到了后期蛇变长了之后就会有bug了。
好了，直接上代码吧：
1）头文件和宏定义
#include#include #include #include #include #define SNAKE_MAX_LENGTH 20 #define SNAKE_HEAD 'H' #define SNAKE_BODY 'X' #define BLANK_CELL '' #define SNAKE_FOOD '$' #define WALL_CELL '*'
2）各种实现函数的声明
/*snake stepping: dy = -1(up) 1(dowm) 0(no move); dx = -1(left), 1(right), 0(no move)*/ void snakemove(int, int); //to write dowm the current location of the snake void put_money(void); void output(void); // to put the current map on the screen void initial_the_game(void); void put_accelerate(void); // @ is a special food which can speed up your snake. int judge(int, int); /* when it comes to ai, it is used to judge whether the next step is movable. */ int dis(int, int); // when it coomes to ai, it is used to calculate the current distence //between the snake head and the food. void welcome(void); // the game introduction. void gameover(void); void edition_handed(void); // the edition in which you can play by yourself. void edition_presentation(void); // the edition in which the snake can go automatically.
3）各种全局变量
// define vars for snake,notice name of vars in c
int snakeX[SNAKE_MAX_LENGTH] = {1, 2, 3, 4, 5};
int snakeY[SNAKE_MAX_LENGTH] = {1, 1, 1, 1, 1};
int snakeLength = 5;
int gamestate = 1;
int current_speed = 600;
int score = 0;
char edition_choose; // for player to choose the edition.
int con = 1; // to judge the initial state of the game;
int energy = 0; // write down the condition to accelerate by eating $.
//the following part is to realize the simple ai .
const char movable[4] = {'a', 'd', 's', 'w'};
int distance[4] = {9999, 9999, 9999, 9999};
int fx = 6, fy = 6; // the coordinate of the food $
4）地图
char map[12][12] =
{"************",
"*XXXXH *",
"* *",
"* *",
"* *",
"* *",
"* $ *",
"* *",
"* @ *",
"* *",
"* *",
"************"};
5）主函数（可选模式）
int main() {
while (con) {
welcome();
int flag = 1;
while (flag) {
edition_choose = getch(); //choose the edition
if (edition_choose == 'h') {
edition_handed();
flag = 0;
}
else if (edition_choose == 'p') {
edition_presentation();
flag = 0;
}
else {
printf("Please press the correct bottom -,- ...\n");
}
}
gameover();
}
return 0;
}
6）手动模式实现
void edition_handed(void) {
system("cls");
output();
char ch = 'd';
while (gamestate) {
switch (ch) {
case 'a': // go left
while (1) {
snakemove(-1, 0);
Sleep(current_speed);
if (gamestate == 0) // to break the loop if the snake hit the wall or itself.
break;
if (kbhit() != 0) { // to change the direction
ch = getch();
if (ch == 's' || ch == 'w')
break;
else
ch = 'a';
}
}
break;
case 'd': // go right
while (1) {
snakemove(1, 0);
Sleep(current_speed);
if (gamestate == 0)
break;
if (kbhit() != 0)
ch = getch();
if (ch == 's' || ch == 'w')
break;
else
ch = 'd';
}
break;
case 's': // go down
while (1) {
snakemove(0, 1);
Sleep(current_speed);
if (gamestate == 0)
break;
if (kbhit() != 0)
ch = getch();
if (ch == 'a' || ch == 'd')
break;
else
ch = 's';
}
break;
case 'w': // go up
while (1) {
snakemove(0, -1);
Sleep(current_speed);
if (gamestate == 0)
break;
if (kbhit() != 0)
ch = getch();
if (ch == 'a' || ch == 'd')
break;
else
ch = 'w';
}
break;
}
if (gamestate == 0)
break;
}
return;
}
7）自动模式实现
void edition_presentation(void) { // for ai
system("cls");
int i, min = 10000;
output();
char ch;
char quit = 'o';
int k;
while (gamestate) { // find the shortest way;
min = 10000;
if (judge(-1, 0)) distance[0] = dis(-1, 0);
if (judge(1, 0)) distance[1] = dis(1, 0);
if (judge(0, 1)) distance[2] = dis(0, 1);
if (judge(0, -1)) distance[3] = dis(0, -1);
for (i = 0; i < 4; i++) {
if (min >= distance[i]) {
min = distance[i];
k = i;
}
}
Sleep(current_speed);
switch (movable[k]) {
case 'a': // go left
snakemove(-1, 0);
break;
case 'd': // go right
snakemove(1, 0);
break;
case 's': // go down
snakemove(0, 1);
break;
case 'w': // go up
snakemove(0, -1);
break;
}
if (gamestate == 0)
break;
system("cls");
output();
}
return;
}
8）其他辅助函数
欢迎界面
void welcome(void) { // just for some introduction
printf("WELCOME TO THE SNAKE'S WORLD !!!!\n");
printf("\n");
printf("\n");
printf("Please choose the edition you want.\n");
printf("\n");
printf("\n");
printf("The 'h' is for the hand-operated and the 'p' is for the simple presentation\n");
printf("\n");
printf("\n");
printf("Attention: the presentation still has a liitle bug, while it can be moving right for a period of time...\n ");
return;
}
游戏结束界面
void gameover(void) { // give you some introduction when you lose the game.
system("cls");
printf("Game over!!!\n");
printf("Do you want to continue? y or n\n");
char start; // in order to judge whether you still want to play the game.
while (1) {
start = getch();
if (start == 'y') {
system("cls");
initial_the_game();
break;
} else if (start == 'n') {
system("cls");
con = 0; // in order to let the game end.
printf("See you next time! ^-^\n");
break;
} else {
printf("Please press the correct buttom.\n");
}
}
}
图像实现方式
void output(void) { // put the cuttent game map.
printf("THE INTERESTING SNAKE GAME CREATED BY LONGJ =,=\n");
printf("use w~s~a~d to control the snake's movement\n");
printf("ATTENTION: the @ can speed up your lovely snake~~\n");
int i, j;
for (i = 0; i < 12; i++) {
for (j = 0; j < 12; j++) {
printf("%c", map[i][j]);
if (j == 11)
printf("\n");
}
}
printf("Your current_speed is %d\n", current_speed);
printf("The number of your food undigested is %d (when it comes to 5, your speed will be accelerated!) \n", energy);
printf("SCORE = %d\n", score);
return;
}
蛇的行走实现
void snakemove(int dx, int dy) { // all the conditions are comparing the head and the next position.
int i;
if (snakeY[snakeLength - 1] + dy == snakeY[snakeLength - 2] && snakeX[snakeLength - 1] + dx == snakeX[snakeLength - 2])
return; // to prevent it go to itslef.
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == 'X') {
gamestate = 0;
return;
}
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '*') {
gamestate = 0;
return;
}
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == ' '
|| map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@') {
map[snakeY[0]][snakeX[0]] = ' '; // clear the former_tail
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@'
&& current_speed > 100) { // what will happen when your snake eats the @
current_speed -= 100;
put_accelerate();
}
for (i = 0; i < snakeLength - 1; ++i) {
snakeX[i] = snakeX[i + 1];
snakeY[i] = snakeY[i + 1];
}
snakeX[snakeLength - 1] += dx;
snakeY[snakeLength - 1] += dy;
for (i = 0; i < snakeLength - 1; i++) // write down the current snake location
map[snakeY[i]][snakeX[i]] = 'X';
map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'H';
}
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '$') {
map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'X';
snakeLength++;
snakeX[snakeLength - 1] = snakeX[snakeLength - 2] + dx;
snakeY[snakeLength - 1] = snakeY[snakeLength - 2] + dy;
map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'H';
score++;
energy++;
if (energy == 5 && current_speed > 50) {
current_speed -= 50;
energy = 0;
}
put_money();
}
system("cls");
output();
return;
}
食物放置的实现
void put_money(void) { /// ai will change the code
int flag = 1;
while (flag) {
srand(time(NULL));
fx = rand() % 12;
fy = rand() % 12;
if (map[fy][fx] == ' ') {
map[fy][fx] = '$';
flag = 0;
}
if (edition_choose == 'p') {
int i;
for (i = 0; i< 4; i++)
distance[i] = 9999;
}
}
return;
}
void put_accelerate(void) {
int x, y, flag = 1;
while (flag) {
srand(time(NULL));
x = rand() % 12;
y = rand() % 12;
if (map[x][y] == ' ') {
map[x][y] = '@';
flag = 0;
}
}
return;
}
ai辅助函数
int dis(int dx, int dy) {
return abs(fx - snakeX[snakeLength - 1] - dx) + abs(fy - snakeY[snakeLength - 1] - dy);
}
int judge(int dx, int dy) {
if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == ' ')
return 1;
else if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '$')
return 1;
else if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@')
return 1;
else
return 0;
}
游戏over后的初始化函数：
void initial_the_game(void) {
int i, j, count = 1;
snakeLength = 5;
gamestate = 1;
fx = fy = 6;
current_speed = 600;
for (i = 0; i < 5; i++)
snakeY[i] = 1;
for (i = 0; i < 5; i++) {
snakeX[i] = count++;
}
for (j = 0; j < 12; j++) {
map[0][j] = '*';
map[11][j] = '*';
}
for (i = 1; i < 11; i++) {
map[i][0] = map[i][11] = '*';
for (j = 1; j < 11; j++)
map[i][j] = ' ';
}
map[fy][fx] ='$';
map[8][4] = '@';
for (i = 0; i< 4; i++) {
distance[i] = 9999;
}
for (i = 0; i < 4; i++)
map[snakeY[i]][snakeX[i]] = 'X';
map[snakeY[4]][snakeX[4]] = 'H';
return;
}
小结：
不难看出，c语言代码比较冗长，而且初始化的函数实现起来十分麻烦，稍有不慎就会全部出错，导致游戏无法持续玩下去，博主当初写的时候就是被坑了很久=_=
因而现在在学c++，希望以后把类的概念之类的东西都弄得更加熟练之后，可以去把这个冗长的c代码改成更加简洁，阅读性更强的c++代码。
（好的，已经更新了，写出了一个比较简单的C++贪吃蛇，的确是思路清晰很多，代码的可读性更高。）
这篇博客给那些想要用c来写贪吃蛇的同学一些参考，运行起来是没有问题的，可以选择性看：）
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持创新互联。
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