.如何理解.NET对象的XML序列化和反序列化
.如何理解.NET对象的XML序列化和反序列化,很多新手对此不是很清楚,为了帮助大家解决这个难题,下面小编将为大家详细讲解,有这方面需求的人可以来学习下,希望你能有所收获。
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.NET对象的XML序列化和反序列化是如何实现的呢?通过下面实例中的xml schema 描述了一个简单的人力资源信息,详细向你介绍.NET对象的XML序列化和反序列化的实现过程其中包含了XML的大部分格式,如XML元素相互嵌套, XML元素既有元素值,又有属性值。
XML序列化和反序列化实现1. 待序列化的类层次结构
[XmlRoot("humanResource")] public class HumanResource { #region private data. private int m_record = 0; private Worker[] m_workers = null; #endregion [XmlAttribute(AttributeName="record")] public int Record { get { return m_record; } set { m_record = value; } } [XmlElement(ElementName="worker")] public Worker[] Workers { get { return m_workers; } set { m_workers = value; } } } public class Worker { #region private data. private string m_number = null; private InformationItem[] m_infoItems = null; #endregion [XmlAttribute("number")] public string Number { get { return m_number; } set { m_number = value; } } [XmlElement("infoItem")] public InformationItem[] InfoItems { get { return m_infoItems; } set { m_infoItems = value; } } } public class InformationItem { #region private data. private string m_name = null; private string m_value = null; #endregion [XmlAttribute(AttributeName = "name")] public string Name { get { return m_name; } set { m_name = value; } } [XmlText] public string Value { get { return m_value; } set { m_value = value; } } }
XML序列化和反序列化实现2. 序列化生成的xml结构
﹤?xml version="1.0" ?﹥ ﹤humanResource xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" record="2"﹥ ﹤worker number="001"﹥ ﹤infoItem name="name"﹥Michale﹤/infoItem﹥ ﹤infoItem name="sex"﹥male﹤/infoItem﹥ ﹤infoItem name="age"﹥25﹤/infoItem﹥ ﹤/worker﹥ ﹤worker number="002"﹥ ﹤infoItem name="name"﹥Surce﹤/infoItem﹥ ﹤infoItem name="sex"﹥male﹤/infoItem﹥ ﹤infoItem name="age"﹥28﹤/infoItem﹥ ﹤/worker﹥ ﹤/humanResource﹥
XML序列化和反序列化实现3. 利用XmlSerializer类进行序列化和反序列化的实现
一般利用缓存机制实现xml文件只解析一次。
public sealed class ConfigurationManager { private static HumanResource m_humanResource = null; private ConfigurationManager(){} public static HumanResource Get(string path) { if (m_humanResource == null) { FileStream fs = null; try { XmlSerializer xs = new XmlSerializer(typeof(HumanResource)); fs = new FileStream(path, FileMode.Open, FileAccess.Read); m_humanResource = (HumanResource)xs.Deserialize(fs); fs.Close(); return m_humanResource; } catch { if (fs != null) fs.Close(); throw new Exception("Xml deserialization failed!"); } } else { return m_humanResource; } } public static void Set( string path, HumanResource humanResource) { if (humanResource == null) throw new Exception("Parameter humanResource is null!"); FileStream fs = null; try { XmlSerializer xs = new XmlSerializer(typeof(HumanResource)); fs = new FileStream( path, FileMode.Create, FileAccess.Write); xs.Serialize(fs, humanResource); m_humanResource = null; fs.Close(); } catch { if (fs != null) fs.Close(); throw new Exception("Xml serialization failed!"); } } }
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